2x^2-8x+17=0

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Solution for 2x^2-8x+17=0 equation:


Simplifying
2x2 + -8x + 17 = 0

Reorder the terms:
17 + -8x + 2x2 = 0

Solving
17 + -8x + 2x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
2 the coefficient of the squared term: 

Divide each side by '2'.
8.5 + -4x + x2 = 0

Move the constant term to the right:

Add '-8.5' to each side of the equation.
8.5 + -4x + -8.5 + x2 = 0 + -8.5

Reorder the terms:
8.5 + -8.5 + -4x + x2 = 0 + -8.5

Combine like terms: 8.5 + -8.5 = 0.0
0.0 + -4x + x2 = 0 + -8.5
-4x + x2 = 0 + -8.5

Combine like terms: 0 + -8.5 = -8.5
-4x + x2 = -8.5

The x term is -4x.  Take half its coefficient (-2).
Square it (4) and add it to both sides.

Add '4' to each side of the equation.
-4x + 4 + x2 = -8.5 + 4

Reorder the terms:
4 + -4x + x2 = -8.5 + 4

Combine like terms: -8.5 + 4 = -4.5
4 + -4x + x2 = -4.5

Factor a perfect square on the left side:
(x + -2)(x + -2) = -4.5

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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